AFNS Physics Chapter 02# Vectors and Equilibrium
-
Scalars and Vectors
Physical quantities can be divided into two groups based on whether they have direction or not.
1.1 Scalar Quantities
KEY CONCEPT: A scalar quantity has only magnitude (size/number). It has NO direction.
- Mass: 5 kg (just a number — no direction needed)
- Temperature: 37°C
- Speed: 60 km/h (how fast, but not which way)
- Distance: 100 m (total path length)
- Time, Energy, Power, Work, Pressure, Density, Volume
1.2 Vector Quantities
KEY CONCEPT: A vector quantity has both magnitude AND direction. It is represented by an arrow.
- Displacement: 5 m North (distance + direction)
- Velocity: 60 km/h East
- Force: 10 N downward
- Acceleration, Momentum, Weight, Torque, Electric Field
| Scalar | Vector |
| Mass | Weight |
| Speed | Velocity |
| Distance | Displacement |
| Energy | Force |
| Temperature | Acceleration |
| Power | Momentum |
QUICK TIP: Most common AFNS trick: Speed vs Velocity and Distance vs Displacement. Speed/Distance = scalar. Velocity/Displacement = vector.
1.3 Representation of Vectors
- Written as bold letter: F or with arrow on top: →F
- Drawn as an arrow: tail is starting point, head shows direction
- Length of arrow = magnitude of vector (to scale)
EXAMPLE: A force of 20 N East is drawn as an arrow of length 2 cm pointing East (using scale: 1 cm = 10 N
-
Vector Addition — Graphical Methods
Vectors cannot be added like ordinary numbers because they have direction. We use special methods.
2.1 Triangle Law of Vector Addition
Place vectors HEAD to TAIL. The resultant is drawn from the tail of the first vector to the head of the last vector.
KEY CONCEPT: Triangle Law: If two vectors A and B are placed head to tail, then the resultant R = A + B is the vector from the tail of A to the head of B.
EXAMPLE: Walk 3 m East, then 4 m North. The resultant displacement = 5 m (from start to finish, at 53° from East). This uses triangle law.
2.2 Parallelogram Law of Vector Addition
Place both vectors with their TAILS at the same point. Complete a parallelogram. The diagonal from the common tail point is the resultant.
KEY CONCEPT: Parallelogram Law: R = √(A² + B² + 2AB cosθ), where θ is the angle between vectors A and B.
EXAMPLE: Two forces: 6 N and 8 N at 90° to each other. R = √(36 + 64 + 0) = √100 = 10 N. Direction: tan α = 8/6 → α = 53°
2.3 Important Special Cases
- Same direction (θ = 0°): R = A + B (maximum resultant)
- Opposite direction (θ = 180°): R = |A − B| (minimum resultant)
- Perpendicular (θ = 90°): R = √(A² + B²) (use Pythagoras)
QUICK TIP: AFNS shortcut: Two equal vectors of magnitude A at angle θ → R = 2A cos(θ/2). If θ = 120°, R = 2A cos60° = 2A × 0.5 = A.
2.4 Subtraction of Vectors
A − B = A + (−B). To subtract B from A, reverse the direction of B (make it −B), then add to A.
EXAMPLE: A = 5 m/s East, B = 3 m/s East. A − B = 5 − 3 = 2 m/s East. | If B was West: A − B = 5 − (−3) = 8 m/s East.
-
Vector Addition — Rectangular Components
The most powerful and precise method of vector addition. Every vector can be split into horizontal (x) and vertical (y) components.
3.1 Resolving a Vector into Components
KEY CONCEPT: Any vector A at angle θ from the x-axis: Horizontal component Ax = A cosθ | Vertical component Ay = A sinθ
EXAMPLE: A force F = 50 N at 30° above horizontal: Fx = 50 cos30° = 50 × 0.866 = 43.3 N | Fy = 50 sin30° = 50 × 0.5 = 25 N
3.2 Finding the Resultant from Components
Add all x-components together and all y-components together, then combine:
- ΣFx = F1x + F2x + F3x + …
- ΣFy = F1y + F2y + F3y + …
- Resultant magnitude: R = √[(ΣFx)² + (ΣFy)²]
- Resultant direction: θ = tan⁻¹(ΣFy / ΣFx)
EXAMPLE: Two forces: F1 = 30 N at 0° and F2 = 40 N at 90°. ΣFx = 30 + 0 = 30 N. ΣFy = 0 + 40 = 40 N. R = √(900+1600) = √2500 = 50 N. θ = tan⁻¹(40/30) = 53°
3.3 Unit Vectors
KEY CONCEPT: Unit vector has magnitude = 1. It shows direction only. i-hat (î) = unit vector along x-axis. j-hat (ĵ) = along y-axis. k-hat (k̂) = along z-axis.
- Any vector A can be written as: A = Ax î + Ay ĵ
- Magnitude of unit vector = 1 always
- |î| = |ĵ| = |k̂| = 1
EXAMPLE: F = 3î + 4ĵ means Fx = 3 N, Fy = 4 N. Magnitude = √(9+16) = 5 N.
QUICK TIP: If asked ‘what is the unit vector of A = 3î + 4ĵ?’ — divide by magnitude: Â = (3î + 4ĵ)/5 = 0.6î + 0.8ĵ
-
Position Vector and Displacement
4.1 Position Vector
A position vector describes the location of a point relative to the origin. If point P has coordinates (x, y), then its position vector r = xî + yĵ.
EXAMPLE: Point P at (3, 4): Position vector r = 3î + 4ĵ. Magnitude |r| = √(9+16) = 5 units.
4.2 Displacement Vector
KEY CONCEPT: Displacement = Final Position − Initial Position = r₂ − r₁. It is a vector quantity showing change in position.
EXAMPLE: Initial position r₁ = 2î + 3ĵ. Final position r₂ = 5î + 7ĵ. Displacement = r₂ − r₁ = 3î + 4ĵ. Magnitude = 5 units, Direction = tan⁻¹(4/3) = 53°
4.3 Distance vs Displacement
| Distance | Displacement |
| Scalar quantity | Vector quantity |
| Total path length | Shortest path (straight line) |
| Always positive | Can be positive, negative or zero |
| Symbol: d or s | Symbol: s (with arrow) or Δr |
| Example: Running 400 m on a track | Example: 0 m if you return to start |
QUICK TIP: Classic AFNS question: A person walks 3 m East then 3 m West. Distance = 6 m. Displacement = 0 m. Distance ≥ Displacement always!
Vector Addition & Components
-
The rectangular components of a vector $\vec{A}$ making an angle $\theta$ with the x-axis are given by:
-
A) $A_x = A \sin\theta$, $A_y = A \cos\theta$
-
B) $A_x = A \cos\theta$, $A_y = A \sin\theta$
-
C) $A_x = A \tan\theta$, $A_y = A \cos\theta$
-
D) $A_x = A \sec\theta$, $A_y = A \csc\theta$
-
Answer: B
-
-
If both rectangular components $A_x$ and $A_y$ of a vector are negative, the vector lies in which quadrant?
-
A) First quadrant
-
B) Second quadrant
-
C) Third quadrant
-
D) Fourth quadrant
-
Answer: C
-
-
Maximum number of rectangular components a vector can have in 3D space is:
-
A) 1
-
B) 2
-
C) 3
-
D) Infinite
-
Answer: C
-
-
Two vectors of magnitudes $3\text{ N}$ and $4\text{ N}$ act at right angles ($90^\circ$) to each other. Their resultant magnitude is:
-
A) $1\text{ N}$
-
B) $5\text{ N}$
-
C) $7\text{ N}$
-
D) $12\text{ N}$
-
Answer: B
-
-
The resultant of two equal forces $F$ acting at an angle of $180^\circ$ to each other is:
-
A) $2F$
-
B) $F$
-
C) Zero
-
D) $\frac{F}{2}$
-
Answer: C
-
2. Unit Vectors & Vector Representation
-
A vector having a magnitude of unity and used only to indicate direction is called a:
-
A) Position vector
-
B) Null vector
-
C) Unit vector
-
D) Free vector
-
Answer: C
-
-
A vector with zero magnitude and arbitrary direction is known as a:
-
A) Unit vector
-
B) Position vector
-
C) Null vector
-
D) Equal vector
-
Answer: C
-
-
The position vector $\vec{r}$ of a point $P(x, y, z)$ in 3D space is written as:
-
A) $x\hat{i} + y\hat{j} + z\hat{k}$
-
B) $x\hat{i} \cdot y\hat{j} \cdot z\hat{k}$
-
C) $(x + y + z)\hat{k}$
-
D) $x\hat{i} – y\hat{j} – z\hat{k}$
-
Answer: A
-
-
The magnitude of the unit vector $\hat{i} + \hat{j}$ is:
-
A) $1$
-
B) $\sqrt{2}$
-
C) $2$
-
D) $0$
-
Answer: B
-
3. Dot (Scalar) Product
-
The scalar product of two mutually perpendicular vectors $\vec{A}$ and $\vec{B}$ is:
-
A) $AB$
-
B) $-AB$
-
C) Zero
-
D) $1$
-
Answer: C
-
-
The self dot product of a unit vector (e.g., $\hat{i} \cdot \hat{i}$) is equal to:
-
A) $0$
-
B) $1$
-
C) $-1$
-
D) Infinity
-
Answer: B
-
-
If $\vec{A} \cdot \vec{B} = AB$, then the angle between $\vec{A}$ and $\vec{B}$ is:
-
A) $0^\circ$
-
B) $45^\circ$
-
C) $90^\circ$
-
D) $180^\circ$
-
Answer: A
-
-
Work done by a force $\vec{F}$ displacing an object through $\vec{d}$ is an example of:
-
A) Vector product
-
B) Scalar product
-
C) Cross product
-
D) Lami’s theorem
-
Answer: B
-
4. Cross (Vector) Product
-
The direction of the cross product $\vec{A} \times \vec{B}$ is determined by:
-
A) Head-to-tail rule
-
B) Left-hand rule
-
C) Right-hand rule
-
D) Fleming’s rule
-
Answer: C
-
-
The magnitude of the cross product $\vec{A} \times \vec{B}$ is maximum when the angle between them is:
-
A) $0^\circ$
-
B) $45^\circ$
-
C) $90^\circ$
-
D) $180^\circ$
-
Answer: C
-
-
For two vectors $\vec{A}$ and $\vec{B}$, the cross product obeys which property?
-
A) $\vec{A} \times \vec{B} = \vec{B} \times \vec{A}$
-
B) $\vec{A} \times \vec{B} = -(\vec{B} \times \vec{A})$
-
C) $\vec{A} \times \vec{B} = 0$
-
D) $\vec{A} \times \vec{B} = \vec{A} \cdot \vec{B}$
-
Answer: B
-
-
The cross product of two parallel vectors is:
-
A) Maximum
-
B) Equal to $AB$
-
C) A null vector
-
D) A unit vector
-
Answer: C
-
-
The area of a parallelogram formed by two adjacent vector sides $\vec{A}$ and $\vec{B}$ is equal to:
-
A) $\vec{A} \cdot \vec{B}$
-
B) $\vert{}\vec{A} \times \vec{B}\vert{}$
-
C) $\frac{1}{2} \vert{}\vec{A} \times \vec{B}\vert{}$
-
D) $AB \cos\theta$
-
Answer: B
-
5. Torque & Equilibrium
-
Torque is defined as the vector product of:
-
A) Force and velocity ($\vec{F} \times \vec{v}$)
-
B) Position vector and force ($\vec{r} \times \vec{F}$)
-
C) Force and acceleration ($\vec{F} \times \vec{a}$)
-
D) Mass and acceleration ($m \vec{a}$)
-
Answer: B
-
-
The SI unit of torque is:
-
A) $\text{N/m}$
-
B) $\text{N}\cdot\text{m}$
-
C) $\text{N}\cdot\text{s}$
-
D) $\text{J/s}$
-
Answer: B
-
-
Torque acting on a body depends upon:
-
A) Magnitude of force only
-
B) Moment arm only
-
C) Both force and moment arm
-
D) Mass of the body only
-
Answer: C
-
-
The First Condition of Equilibrium states that:
-
A) $\sum \vec{\tau} = 0$
-
B) $\sum \vec{F} = 0$
-
C) $\sum \vec{p} = 0$
-
D) $\sum \vec{v} = 0$
-
Answer: B
-
-
If a body is moving with uniform velocity, it is said to be in:
-
A) Static equilibrium
-
B) Dynamic equilibrium
-
C) Unstable equilibrium
-
D) Non-equilibrium
-
Answer: B
-
-
The Second Condition of Equilibrium ensures that the body has no:
-
A) Translational acceleration
-
B) Rotational acceleration
-
C) Linear velocity
-
D) Mass
-
Answer: B
-
-
Two equal, opposite, and non-collinear parallel forces acting on a body form a:
-
A) Resultant force
-
B) Couple
-
C) Neutral force
-
D) Moment arm
-
Answer: B
-
Good Mashallah
Very helpful! Thanks to admine, for that Quiz and practice test..